請幫忙解答,求未知數

2010-10-24 6:41 pm
1) (5d/4)-d = 1/2

2) e/3 = 2+(e/2)

3) 9+x = (7-x)/3

4) Y+[(3Y+2)/4] = 11

5) 3 = 2K/5 - (4-K)

6) 5- [(3n-2)/8] + [(n+2)/4] = [(1-2n)/3]

7) 0.4(0.6p-0.25) = 1/5[7/10p - 1/2(p-1)]

回答 (1)

2010-10-24 7:10 pm
✔ 最佳答案
1)
(5d/4)-d = 1/2
5d - 4d = 2
d = 2

2)
e/3 = 2+(e/2)
2e = 12 + 3e
2e - 3e = 12
-e = 12
e = -12

3)
9+x = (7-x)/3
27 + 3x = 7 - x
3x + x = 7 - 27
4x = -20
x = -5

4)
Y+[(3Y+2)/4] = 11
4Y + 3Y + 2 = 44
7Y = 44 - 2
7Y = 42
Y = 6

5)
3 = 2K/5 - (4-K)
15 = 2K - 20 + 5K
15 + 20 = 7K
35 = 7K
K = 5

6)
5- [(3n-2)/8] + [(n+2)/4] = [(1-2n)/3]
5*24 - 3(3n-2) + 6(n+2) = 8(1-2n)
120 - 9n + 6 + 6n + 12 = 8 - 16n
138 - 3n = 8 - 16n
16n - 3n = 8 - 138
13n = -130
n = -10

7)
0.4(0.6p-0.25) = 1/5[7/10p - 1/2(p-1)]
(2/5)[(3p/5)-(1/4)] = (1/5)[(7p/10)-(p-1)/2]
2[(3p/5)-(1/4)] = (7p/10)-(p-1)/2
(6p/5) - (1/2) = (7p/10) - (p-1)/2
2*6p - 5 = 7p - 5(p-1)
12p - 5 = 7p - 5p + 5
12p - 7p +5p = 5 + 5
10p = 10
p = 1



收錄日期: 2021-04-23 23:13:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101024000051KK00341

檢視 Wayback Machine 備份