以下兩題公式主項變換為括號內的字母:
1) Ax + By + C = 0 (x)
答案是 x= -By+C over A (不懂列式)
2) v^2 = u^2 + 2as (s)
答案是 s= v^2 -u^2 over 2a (不懂列式)
化簡代數式1題:
1) 8x+13 / 3(x-1) + 3(2x+3) / 2(1-x) + x / 2(x-1)
答案是 : 1/6 (不懂列式)
幫忙計計代數式
2010-10-24 8:48 am
回答 (2)
2010-10-24 7:09 pm
✔ 最佳答案
Ax + By - C = 0 (x)Ax=C-By
x=(C-By)/A
_______________
v^2 = u^2 + 2as (s)v^2-u^2=2ass=(v^2-u^2)/2a__________________(8x+13 / 3(x-1)) + (3(2x+3) / 2(1-x)) + (x / 2(x-1))
(8x+13 / 3(x-1)) - (3(2x+3) / 2(x-1)) + (x / 2(x-1))
(2(8x+13)-3(3(2x+3))+3x)/6(x-1)
(16x+26-18x-27+3x)/6(x-1)
(x-1)/6(x-1)
1/6
2010-10-24 11:09:20 補充：
.
參考: , 魔龍帝齊格益力多
2010-10-24 8:20 pm
1)
Ax + By + C = 0 (x)
Ax = -By - C
x = -(By + C) / A
2)
v^2 = u^2 + 2as (s)
2as = v^2 - u^2
s = (v^2 -u^2) / (2a)
3)
8x+13 / 3(x-1) + 3(2x+3) / 2(1-x) + x / 2(x-1)
= (8x+13)/[3(x-1)]} - [3(2x+3)]/[2(x-1) + x / [2(x-1)]
= {[(8x+13)/3] - [(6x+9)/2] + (x/2)} / (x-1)
= [2(8x+13)-3(6x+9)+3x] / [6(x-1)]
= (16x+26-18x-27+3x) / [6(x-1)]
= (x-1) / [6(x-1)]
= 1/6
Ax + By + C = 0 (x)
Ax = -By - C
x = -(By + C) / A
2)
v^2 = u^2 + 2as (s)
2as = v^2 - u^2
s = (v^2 -u^2) / (2a)
3)
8x+13 / 3(x-1) + 3(2x+3) / 2(1-x) + x / 2(x-1)
= (8x+13)/[3(x-1)]} - [3(2x+3)]/[2(x-1) + x / [2(x-1)]
= {[(8x+13)/3] - [(6x+9)/2] + (x/2)} / (x-1)
= [2(8x+13)-3(6x+9)+3x] / [6(x-1)]
= (16x+26-18x-27+3x) / [6(x-1)]
= (x-1) / [6(x-1)]
= 1/6
收錄日期: 2021-04-23 23:14:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101024000051KK00070