Maths唔識抵死題(QUICK!!!!!!!!!!!!)
2010-10-22 2:36 am
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TRY.... TRY .............................TRY
回答 (1)
2010-10-22 3:05 am
✔ 最佳答案
1/(x+1)(x-k) = A/(x+1) + B/(x-k)1 = A(x-k) + B(x+1)
when x = k, B(k+1) = 1
B = 1/(k+1)
when x = -1, A(-1-k) = 1
A = -1/(1+k)
Hence,
1/(x+1)(x-k) = A/(x+1) + B/(x-k)
= -1/(1+k)(x+1) + 1/(k+1)(x-k)
= 1/(1+k) [1/(x-k) - 1/(x+1)]
Hence, a = k+1
參考: Hope the solution can help you^^”
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101021000051KK00936