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Maths唔識抵死題(QUICK!!!!!!!!!!!!)
2010-10-22 1:31 am
回答 (1)
2010-10-22 1:36 am
✔ 最佳答案
Let 2/(x-3)(x+5)=A/(x-3)+B(x+5)RHS
=(Ax+5A+Bx-3B)/(x-3)(x+5)
=((A+B)x+(5A-3B))/(x-3)(x+5)
Compare the coefficient of x and constant
A+B=0---(1)
5A-3B=2---(2)
(1)x5-(2)
(5A+5B)-(5A-3B)=0x5-2
5B+3B=-2
8B=-2
B=-1/4
A-1/4=0
A=1/4
So
2/(x-3)(x+5)
=1/4(x-3)-1/4(x+5)
收錄日期: 2021-04-23 20:46:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101021000051KK00810