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2(3a+1)-4(3-2a)
x(2-3x)+3(x-4)
q^2-(p+q)^2
(3m-1)(2m+5)-3(2-m)
p(1-p)(2-p)
(6x+y)^2-3(x^2+y^2)
中二數學多項式(三)
2010-10-20 4:44 am
回答 (4)
2010-10-21 7:06 am
2(3a+1)-4(3-2a)
=6a+2-12+8a
=14a-10
x(2-3x)+3(x-4)
=2x-3x^2+3x-12
=-3x^2+5x-12
q^2-(p+q)^2
=q^2-(p^2+2pq+q^2)
=q^2-p^2-2pq-q^2
=-p^2-2pq
(3m-1)(2m+5)-3(2-m)
=6m^2+15m-2m-5-6+3m
=6m^2+16m-11
p(1-p)(2-p)
=p(2-p-2p+p^2)
=2p-p^2-2p^2+p^3
=2p-3p^2+p^3
(6x+y)^2-3(x^2+y^2)
=36+12y+y^2-3x^2-3y^2
=36+12y-2y^2-3x^2
=6a+2-12+8a
=14a-10
x(2-3x)+3(x-4)
=2x-3x^2+3x-12
=-3x^2+5x-12
q^2-(p+q)^2
=q^2-(p^2+2pq+q^2)
=q^2-p^2-2pq-q^2
=-p^2-2pq
(3m-1)(2m+5)-3(2-m)
=6m^2+15m-2m-5-6+3m
=6m^2+16m-11
p(1-p)(2-p)
=p(2-p-2p+p^2)
=2p-p^2-2p^2+p^3
=2p-3p^2+p^3
(6x+y)^2-3(x^2+y^2)
=36+12y+y^2-3x^2-3y^2
=36+12y-2y^2-3x^2
2010-10-21 1:44 am
2(3a+1)-4(3-2a)
=-2a-10
x(2-3x)+3(x-4)
=-3x^2+5x-12
q^2-(p+q)^2
=p^2+2pq
(3m-1)(2m+5)-3(2-m)
=6m^2+10m-11
p(1-p)(2-p)
=2p-p^2-2p^2+p^3
(6x+y)^2-3(x^2+y^2)
=9x^2+12xy-2y^2
=-2a-10
x(2-3x)+3(x-4)
=-3x^2+5x-12
q^2-(p+q)^2
=p^2+2pq
(3m-1)(2m+5)-3(2-m)
=6m^2+10m-11
p(1-p)(2-p)
=2p-p^2-2p^2+p^3
(6x+y)^2-3(x^2+y^2)
=9x^2+12xy-2y^2
2010-10-20 4:53 am
2(3a+1)-4(3-2a)
=-2a-10
x(2-3x)+3(x-4)
=-3x^2+5x-12
q^2-(p+q)^2
=p^2+2pq
(3m-1)(2m+5)-3(2-m)
=6m^2+10m-11
p(1-p)(2-p)
=2p-p^2-2p^2+p^3
(6x+y)^2-3(x^2+y^2)
=9x^2+12xy-2y^2
=-2a-10
x(2-3x)+3(x-4)
=-3x^2+5x-12
q^2-(p+q)^2
=p^2+2pq
(3m-1)(2m+5)-3(2-m)
=6m^2+10m-11
p(1-p)(2-p)
=2p-p^2-2p^2+p^3
(6x+y)^2-3(x^2+y^2)
=9x^2+12xy-2y^2
2010-10-20 4:52 am
1.14a-10
2.5x-3x^2-12
3.-p^2-2pq
4.6m^2+16m-11
5.p^3-3p^2+2p
6.36x+12xy-3x^2-2y^2
2.5x-3x^2-12
3.-p^2-2pq
4.6m^2+16m-11
5.p^3-3p^2+2p
6.36x+12xy-3x^2-2y^2
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收錄日期: 2021-04-13 17:35:24
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