中二數學多項式(三)

2(3a+1)-4(3-2a)
=6a+2-12+8a
=14a-10
x(2-3x)+3(x-4)
=2x-3x^2+3x-12
=-3x^2+5x-12
q^2-(p+q)^2
=q^2-(p^2+2pq+q^2)
=q^2-p^2-2pq-q^2
=-p^2-2pq
(3m-1)(2m+5)-3(2-m)
=6m^2+15m-2m-5-6+3m
=6m^2+16m-11
p(1-p)(2-p)
=p(2-p-2p+p^2)
=2p-p^2-2p^2+p^3
=2p-3p^2+p^3
(6x+y)^2-3(x^2+y^2)
=36+12y+y^2-3x^2-3y^2
=36+12y-2y^2-3x^2

2(3a+1)-4(3-2a)

=-2a-10

x(2-3x)+3(x-4)

=-3x^2+5x-12

q^2-(p+q)^2

=p^2+2pq

(3m-1)(2m+5)-3(2-m)

=6m^2+10m-11

p(1-p)(2-p)

=2p-p^2-2p^2+p^3

(6x+y)^2-3(x^2+y^2)

=9x^2+12xy-2y^2

2(3a+1)-4(3-2a)

=-2a-10

x(2-3x)+3(x-4)

=-3x^2+5x-12

q^2-(p+q)^2

=p^2+2pq

(3m-1)(2m+5)-3(2-m)

=6m^2+10m-11

p(1-p)(2-p)

=2p-p^2-2p^2+p^3

(6x+y)^2-3(x^2+y^2)

=9x^2+12xy-2y^2

1.14a-10
2.5x-3x^2-12
3.-p^2-2pq
4.6m^2+16m-11
5.p^3-3p^2+2p
6.36x+12xy-3x^2-2y^2