#include <stdio.h>
int main()
{
int numberoftermstobeaded,n;
int thefirstnumber,a;
int thedifferencebetweeneachnumber,d;
float sum;
n=100;
a=1;
d=1;
sum=(n/2)(2*a+(n-1)d);
printf("the sum of 1 to 100 is %f/n",sum );
getchar();
return 0;
}
我唔明咩叫做 a can not be used as a function
c programming 高手請入
2010-10-18 5:12 pm
回答 (2)
2010-10-19 1:48 am
✔ 最佳答案
編寫程序和平時寫的方程式不一樣，編譯器需要100%明確。例如相乘不能寫成 (a)(b)，一定要用星號，寫成 (a)*(b)，有些舊點的編譯器甚至連加多個括都可能error。只接受 a*b。
sum=(n/2)(2*a+(n-1)d);
應該要寫成 sum = (n/2)*(2*a+(n-1)*d) ;
2010-10-18 8:42 pm
sum=(n/2)(2*a+(n-1)d);
This line is incorrect. There is a missing operator. Maybe it should be:
sum = (n/2) (2*a + (n-1) d );
This line is incorrect. There is a missing operator. Maybe it should be:
sum = (n/2) (2*a + (n-1) d );
收錄日期: 2021-04-26 11:27:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101018000051KK00232