Slope = –2, passing through (0, –3)?

point slope form:
y – y1 = m(x – x1)
m is your slope, and the point is (x1, y1), so simply plug these values in.
y - (-3) = -2(x - 0)
y + 3 = -2(x - 0)
To get it to slope intercept form, simply isolate the y by subtracting 3 from both sides of the equation.
y = -2x - 3
This tells us that the slope is -2 (which we already knew) and that this line crosses the y axis at -3.

Hope this helps!

0 3 Slope

Yeah it's possible

y = mx + b
y=-3, m= -2, x=0

-3 =-2(0)+ b
-3 = 0 +b
-3 =b

y = -2x -3

y = -2 x-3

y-y1=m(x-x1) is point slope formula so just plug in your pts
y+3=-2x
slope intercept is y=mx+b
y=-2x+3

y = - 2x - 3