chem equilibrium
2010-10-17 9:17 am
200 cm^3 of a solution 1.6X 10^-5 mole of Pb 2+ and 4X 10^-3 mole of F+ in equilibrium with solid of PbF2 wt is the ksp value of PbH2
回答 (1)
2010-10-17 10:49 am
✔ 最佳答案
PbF2 <======> Pb(2+) + 2F(-) Ksp = [Pb(2+)] x [F(-)]^2
conc. of Pb(2+) = no. of mole / volume
= 1.6E-5 / (200/1000) = 0.00008 M
conc. of F(-) = 4E-3 / (200/1000) = 0.02 M
Ksp of PbF2 = 0.00008 x (0.2)^2 = 3.2E-8 M^3
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