一條數學簡化題目

[(2 x^2 y / -3 x y )^4] [(9 x y / 4 y^3)^2]
(16(x^8)(y^4)/(81)(x^4)(y^4))*(81x^2y^2/16y^6)
(16x^4/81)*(81x^2/16y^4)
x^6/y^4

2010-10-16 18:02:12 補充：
Explanation:
[(2 x^2 y / -3 x y )^4]

((2)^4)((x^2)^4)(y^4)/((-3)^4)((x)^4)((y)^4)
(16(x^8)(y^4)/(81)(x^4)(y^4))
...................

2010-10-16 18:06:43 補充：
If the indics of questions
are odd number,the sign doesnt need to change!

For example:
(-3)^3=-27

(-9)^3=-729

[(2 x^2 y / -3 x y )^4] [(9 x y / 4 y^3)^2]
=(2x^2．y)^4/(-3xy)^4‧(9xy)^2/(4y^3)^2
=(16x^8．y^8 / 81x^4．y^4) x (81x^2．y^2 / 16y^6)
=(x^8．y^4 / x^4．y^4) x (x^2．y^2 / y^6)
=x^6/y^4

哦...好易姐...

你係因為個-3^4唔記得有括號...(-3)^4=3^4

咁就OK啦~