Let y=(x^2)√(1-x)
find (dy)/(dx)
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differentitation(急)
2010-10-15 4:25 am
回答 (3)
2010-10-16 12:06 pm
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參考: My Maths knowledge
2010-10-15 5:06 am
y = x^2√(1 - x)y^2 = x^4(1 - x) = x^4 - x^5
2ydy/dx = 4x^3 - 5x^4
dy/dx
= (4x^3 - 5x^4)/[2x^2√(1 - x)]
= (4x - 5x^2)/[2√(1 - x)]
or 2x/√(1 - x) - 5x^2/2√(1 - x)
2ydy/dx = 4x^3 - 5x^4
dy/dx
= (4x^3 - 5x^4)/[2x^2√(1 - x)]
= (4x - 5x^2)/[2√(1 - x)]
or 2x/√(1 - x) - 5x^2/2√(1 - x)
2010-10-15 4:43 am
Using product rule and ;
the chain rule to differentiate √(1-x)
the chain rule to differentiate √(1-x)
收錄日期: 2021-04-13 17:34:20
原文連結 [永久失效]:
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