中一數學題 好急!!!!

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以下都是本人的一些意見，如有錯誤請多多指教～～～

1) j / 10 + 2 / 5 = 1

j / 10 + 4 / 10 = 1

(j + 4) / 10 = 1

j + 4 = 10

j = 6

2) 5 = 1 / 2 - e / 8

1 / 2 - e / 8 = 5

4 / 8 - e / 8 = 5

(4 - e) / 8 = 5

4 - e = 40

-e = 36

e = -36

3) 1 / 3 = (5 - 3h) / 6

(5 - 3h) / 6 = 1 / 3

5 - 3h = 2

-3h = 2 - 5

h = (-3) / (-3)

h = 1

4) 3u + 4 = 2 / 5

5(3u + 4) = 2

15u + 20 = 2

15u = -18

u = -18 / 15

5) (6 + m) / 2 = 13 / 2

6 + m = (13 / 2) x 2

6 + m = 13

m = 7

6) -10y = 39 + y

-10y - y = 39

-11y = 39

y = 39 / (-11)

y = -39 / 11

希望以上解答可以幫到你～～～～～

2010-10-13 21:23:31 補充：
忘了約簡︰

u = -18 / 15

u = -6 / 5

第一題J=6
第二題E=-36
第三題 H=1
第四題 U=1.2
第五題M=7
第六題Y=-3

1. j over 10 + 2 over 5 =1
j/10 + 2/5 = 1
j/10 = 3/5
j = 3*10/5
j = 6

2 5=1 over 2-e over 8
5 = 1/2 - e/8
e/8 = -9/2
e = -9*8/2
e = -36

3 1over 3 = 5-3h over 6
1/3 = 5 - 3h/6
1/3 = 5 - h/2
h/2 = 14/3
h = 28/3

or
1/3 = (5-3h)/6
2 = 5 - 3h
3h = 5-2
3h = 3
h = 1

4 3u+4 = 2over 5
3u+4 = 2/5
15u + 20 = 2
15u = -18
u = -5/6

5.6+m over 2 = 13 over 2
(6+m)/2 = 13/2
6+m = 13
m = 7
or
6 + m/2 = 13/2
m/2 = 1/2
m = 1
6.-10y=39+y
我的方法是以上全部

1. j over 10 + 2 over 5 =1
j/10 + 2/5 = 1
j/10 = 3/5
j = 3*10/5
j = 6

2 5=1 over 2-e over 8
5 = 1/2 - e/8
e/8 = -9/2
e = -9*8/2
e = -36

3 1over 3 = 5-3h over 6
1/3 = 5 - 3h/6
1/3 = 5 - h/2
h/2 = 14/3
h = 28/3

or
1/3 = (5-3h)/6
2 = 5 - 3h
3h = 5-2
3h = 3
h = 1

4 3u+4 = 2over 5
3u+4 = 2/5
15u + 20 = 2
15u = -18
u = -5/6

5.6+m over 2 = 13 over 2
(6+m)/2 = 13/2
6+m = 13
m = 7
or
6 + m/2 = 13/2
m/2 = 1/2
m = 1
6.-10y=39+y

2010-10-13 21:05:33 補充：
6. -11y = 39
y = -39/11