若f(x)=3x+2,求下列各題的值。
(e) f(k+1)
(f) f(k+1)+3
(g) f(k+2)-f(k-2)
3題數 關於函數
2010-10-13 1:16 am
回答 (2)
2010-10-13 1:19 am
✔ 最佳答案
若f(x)=3x+2,求下列各題的值。(e) f(k+1)= 3(k+1) + 2= 3k + 3 + 2= 3k + 5
(f) f(k+1)+3= (3k + 5) + 3 from(e)
= 3k + 8
(g) f(k+2)-f(k-2)
= 3(k+2) + 2 - 3(k-2) - 2= 3(k+2 - k + 2)= 3*4= 12
參考: Hope the solution can help you^^”
2010-10-13 1:24 am
若f(x)=3x+2,求下列各題的值。
(e) f(k+1)
= 3(k+1) + 2
= 3k + 3 + 2
= 3k + 5
(f) f(k+1)+3
= (3k + 5) + 3 from(e)
= 3k + 8
(g) f(k+2)-f(k-2)
= 3(k+2) + 2 - 3(k-2) - 2
= 3(k+2 - k + 2)
= 3*4
= 12
(e) f(k+1)
= 3(k+1) + 2
= 3k + 3 + 2
= 3k + 5
(f) f(k+1)+3
= (3k + 5) + 3 from(e)
= 3k + 8
(g) f(k+2)-f(k-2)
= 3(k+2) + 2 - 3(k-2) - 2
= 3(k+2 - k + 2)
= 3*4
= 12
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