又一條難數,高人請進

If (a-b)^2=m and (a+b)^2=n,express(a-b)^3(a+b)^5(b^2-a^2) in terms of m and n
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(a-b)^3(a+b)^5(b^2-a^2)
(a-b)^3(a+b)^5(b-a)(a+b)
-(a-b)^3(a+b)^5(a-b)(a+b)
-(a-b)^4(a+b)^6
-m^2n^3

2010-10-11 20:34:28 補充：
I think that you typed wrong again...........

2010-10-11 20:36:59 補充：
I doesnt determine that you really typed wrong last time,so I did not answered.

I hope that I doesnt guess wrong your meaning

2010-10-11 21:22:44 補充：
i doesnt determine that you really typed wrong last time,so I did not answer

(a-b)^3(a+b)^5(b^2-a^2)

=(a-b)^2(a-b)(a+b)^2(a+b)^2(a+b)(b-a)(a+b)

=m(a-b)(n)(n)(a+b)(b-a)(a+b)

=mn^2(a+b)^2(a-b)(b-a)

=mn^3[(a-b)(b-a)]

=mn^3[-(a-b)(a-b)]

=mn^3[-(a-b)^2]

=mn^3(-m)

=(-m^2)(n^3)

有錯請指正!!


2010-10-11 20:43:12 補充：
這方法你應該易睇吧==