請問呢D代數題點做?

2010-10-12 4:18 am
Solve the following equations.
(1) 6x-5=4x+3
(2)7m+15-2m=20-5m
(3)2(2k+3)-5=3(k+7)

請詳解。
萬分感激!!!>_<

回答 (2)

2010-10-12 4:38 am
✔ 最佳答案
Solve the following equations.
(1) 6x-5=4x+3
6x - 4x = 3 + 5
2x = 8
x = 4
(2) 7m+15-2m=20-5m
7m-2m+5m = 20-15
10m = 5
m = 1/2
(3) 2(2k+3)-5=3(k+7)
4k+6-5=3k+21
4k-3k=21+5-6
k=20
參考: Knowledge is power.
2010-10-12 4:51 am
E题张有X果D数调过去左边,当然,当左边调去右边(/右调左)时要调翻D正负数,即 ' + '变 ' - ', ' - '变' + '
(1) 6x-5=4x+3
6x-4x=3+5
2x=8
x=4

(2)7m+15-2m=20-5m
7m-2m+5m=2015
10m=5
m=0.5

E题都系张有X果D数调过去左边,但之前就乘走左个括号先,
如下题: 2(2k+3)-5
写成:2(2k)+2(3)-5 (E个系步骤,计数时唔洗写落去)
= 4k+6-5

(3)2(2k+3)-5=3(k+7)
4k+6-5=3k+21
4k-3k=21-6+5
k=15+5
k=20


希望帮到你~
參考: ME


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