A 12.0-g sample of an unknown metal is heated to 90.5°C and is placed in a perfectly insulated container along with 148.g of water at an initial temperature of 21.65°C. After a short time the temperature of both the metal and water become equal at 25.00°C.
The specific Heat Capacity of water is 4.18 J/g/K in this temperature range.
What is the specific heat capacity of the metal?
Specific Heat Capacity 10 pt
2010-10-10 4:57 pm
回答 (2)
2010-10-10 8:00 pm
✔ 最佳答案
let x J g^-1 k^-1 be the heat capacity of the unknown metalEnergy released by the metal=12x(90.5-25)=786x
Energy absorbed by water=148(4.18)(25-21.65)=2072.444J
Energy released=Energy absorbed
786x=2072.444
x=2.64
2010-10-11 1:27 am
delta temperature of metal is 90.5 - 25 = 65.5 K
delta temperature of water is 25 - 21.65 = 3.35 K
let the specific heat capacity of the metal is x J/g/K
since, specific heat of the metal = specific heat of the water
then
12 * 65.5 * x = 148 * 4.18 * 3.35
786 x = 2072.444
x = 2.6367
so, the specific heat capacity of the metal is 2.6367 J/g/K
delta temperature of water is 25 - 21.65 = 3.35 K
let the specific heat capacity of the metal is x J/g/K
since, specific heat of the metal = specific heat of the water
then
12 * 65.5 * x = 148 * 4.18 * 3.35
786 x = 2072.444
x = 2.6367
so, the specific heat capacity of the metal is 2.6367 J/g/K
參考: myself
收錄日期: 2021-04-29 18:28:08
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