Help~ F.1's Maths question
1) n/5 +10= 2/5 n
2) 1/2 = 10-3u / 8
Please write the neatly STEP, please!
回答 (4)
1.n/5+10=2/5 n
10=2/5 n-n/5
10 x5=(2/5 n-n/5) x5
50=2/5 n x5-n/5 x5
50=2n-n
50=n
2.1/2=10-3u/8
1/2+3u/8=10
(1/2+3u/8) x8=10 x8
4+3u=80
3u=80+4
u=84/3
u=28
1) n/5 +10= 2/5 n
1/5n -2/5n =-10
-1/5n=-10
n=50
2) 1/2 = 10-3u / 8
3u/8=10-1/2
3u/8=20/2-1/2
3u/8=19/2
3u*2=19*8
6u=152
u=76/3
u=25/1/3
2010-10-11 06:55:36 補充:
ξ沁ξ 沁ξ 沁ξ 沁ξ 沁ξ→ ∞ 錯了
q1:my ans. as same as ur ans.
2010-10-11 06:57:44 補充:
q2:
ur list is 1/2=(10-u)/8,not his question
2010-10-11 06:59:33 補充:
q2:
ans is u=25-1/3
re003
ur question (2)'s list is 1/2=(10-u)/8,not his question
1) n/5 +10= 2/5 n
1/5n -2/5n =-10
-1/5n=-10
n=50
2) 1/2 = 10-3u / 8
3u/8=10-1/2
3u/8=20/2-1/2
3u/8=19/2
3u*2=19*8
6u=152
u=76/3
u=25 又 1/3
收錄日期: 2021-04-13 17:34:23
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