1條F.3 MATHS 10 POINT
回答 (2)
2010-10-07 4:05 am
✔ 最佳答案
4 / (√ 2 + 1) - 6√ 5 / (√ 3 - 2)= 4(√ 2 - 1) / [(√ 2 + 1)(√ 2 - 1)] - (6√ 5)(√ 3 + 2) / [(√ 3 - 2)(√ 3 + 2)]= 4(√ 2 - 1) / (2 - 1) - (6√ 5)(√ 3 + 2) / (3 - 2²)= 4(√ 2 - 1) / 1 - (6√ 5)(√ 3 + 2) / - 1= 4(√ 2 - 1) + (6√ 5)(√ 3 + 2)= 4√ 2 - 4 + 6√15 + 12√5= 2(2√2 + 6√5 + 3√15 - 2)
2010-10-07 4:03 am
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