Figure: http://img408.imageshack.us/img408/8150/63561088.png
In the figure, two circles intersect at points P and Q. AB is the tangent to
the smaller circle at T. TPS and TQR are straight lines. Angle ATP = 62 and
angle QRS = 55. Find angle PSR and angle BTQ.
F5 Maths
2010-10-06 3:10 am
回答 (1)
2010-10-06 3:24 am
✔ 最佳答案
圖片參考：http://img408.imageshack.us/img408/8150/63561088.png
Joint PQ ,ㄥTQP = 62°(∠in alt. segment)
ㄥPSR = ㄥTQP = ㄥATP (ext. ∠s, cyclic quad.) = 62°
ㄥBTQ = ㄥTPQ(∠in alt. segment) = ㄥQRS(ext.∠= int. opp.∠) = 55°
2010-10-05 19:48:36 補充：
ㄥPSR = ㄥTQP (ext. ∠s, cyclic quad.) = ㄥATP(∠in alt. segment) = 62°
收錄日期: 2021-04-21 22:16:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101005000051KK00929