F5 Maths

Since, ABCD is a semi-circle.ÐABD = ÐACD = 90°Given that arc AB = arc CD, ∴ ÐBDA = ÐCAD (equal arc, equal Ð)∴ ÐBDA = 90° – p – q p + q = 90° – p – q 2p + 2q = 90° p + q = 45° Twp possible sets of p and q:p = 20°, q = 25° and p = 25° and q = 20°

If you have any questions, please feel free to ask.