F.5 MATHS

2010-10-02 7:28 pm
Find dy/dx for each of the following function.

y=[(x^4)-6)](3x-8)

回答 (2)

2010-10-02 7:34 pm
✔ 最佳答案
Find dy/dx for each of the followingfunction.
y=[(x^4)-6)](3x-8)Soly=(x^4-6)(3x-8)=3x^5-8x^4-18x+48dy/dx=d(3x^5-8x^4-18x+48)/dx=15x^4-32x^3-18
2010-10-02 7:56 pm
y = (x^4 - 6)(3x - 8)
dy/dx
= (x^4 - 6)*3 + (3x-8)*4x^3 (By product rule)
= 3(x^4 - 6) + 4x^3 (3x-8)
= 3x^4 - 18 + 12x^4 - 32x^3
= 15x^4 - 32x^3 - 18


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