(-7+10i)+(9+6i)除(3i)=.....

究竟係

[ (-7+10i) + (9+6i) ] / 3i

定係

(-7+10i) + [(9+6i)/(3i) ]

2010-10-01 22:32:39 補充：
* 假設題目為 (-7+10i) + [ (9+6i) / 3i ]

(-7+10i) + [ (9+6i) / 3i ]
= ( -7+10i) + (9/3i) + 2
= -7 + 10i + (-3i) +2
= ( -5 + 7i )

2010-10-02 23:16:34 補充：
a/bi
= ai / bi^2
= -ai/b

【Complex number solution】

=-7+10i + (0+18)/9 - 27i/9, conjugate conjugate
= -7 +10i + 2 -3i
= -5 +7i

2010-10-01 23:41:47 補充：
i, may represent imaginary part

(-7+10i)+(9+6i)除(3i)
=-7+10i+9+6i除3i
=-7+10i+9+2i
=-7+9+10i=2i
=2+12i