(-7+10i)+(9+6i)除(3i)=咩
請列明步驟
(-7+10i)+(9+6i)除(3i)=.....
2010-10-02 6:16 am
回答 (3)
2010-10-02 6:32 am
✔ 最佳答案
究竟係[ (-7+10i) + (9+6i) ] / 3i
定係
(-7+10i) + [(9+6i)/(3i) ]
2010-10-01 22:32:39 補充：
* 假設題目為 (-7+10i) + [ (9+6i) / 3i ]
(-7+10i) + [ (9+6i) / 3i ]
= ( -7+10i) + (9/3i) + 2
= -7 + 10i + (-3i) +2
= ( -5 + 7i )
2010-10-02 23:16:34 補充：
a/bi
= ai / bi^2
= -ai/b
2010-10-02 7:40 am
【Complex number solution】
=-7+10i + (0+18)/9 - 27i/9, conjugate conjugate
= -7 +10i + 2 -3i
= -5 +7i
2010-10-01 23:41:47 補充：
i, may represent imaginary part
=-7+10i + (0+18)/9 - 27i/9, conjugate conjugate
= -7 +10i + 2 -3i
= -5 +7i
2010-10-01 23:41:47 補充：
i, may represent imaginary part
2010-10-02 6:41 am
(-7+10i)+(9+6i)除(3i)
=-7+10i+9+6i除3i
=-7+10i+9+2i
=-7+9+10i=2i
=2+12i
=-7+10i+9+6i除3i
=-7+10i+9+2i
=-7+9+10i=2i
=2+12i
收錄日期: 2021-04-13 17:33:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101001000051KK01673