F.4 M2 Chap 2

2010-10-02 3:30 am
k is identical to Pk(k-1)-Qk(k+1), find the values of P and Q

回答 (1)

2010-10-02 3:50 am
✔ 最佳答案
Pk(k-1)-Qk(k+1) = kPk^2 - Pk - Qk^2 - Qk = k(P - Q)k^2 - (P + Q)k = kSoP - Q = 0 .....(1)and - (P + Q) = 1.....(2)By (1) P = Q , sub it to (2) :- (P + P) = 1P = - 1/2Q = - 1/2


收錄日期: 2021-04-21 22:17:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101001000051KK01343

檢視 Wayback Machine 備份