f.3 math

2x+3y-1=0-------------1
{
3x+5y-1=0-------2
_________________

From1:
x=1-3y/2-------------3

Sub. 3 into 2:
3(1-3y/2)+5y-1=0
3-9y+10y=2
3+y=2
y=-1

Put y=-1 into 3:
x=2
________________
Let x be (1/a),y be (1/b):
so.........2x+3y=1-------13x+5y=1---------2
_____________
x=1/2x=-1

2010-10-01 12:46:23 補充：
2x+3y-1=0
(2x+3y=1)
____________
3x+5y-1=0
3x+5y=1

2010-10-01 12:49:02 補充：
Correction:
a=1/2

b=-1

2010-10-01 14:17:35 補充：
OK:
From1(由1)

Sub. 3 into 2(把3代入2)

Put y=-1 into 3:(把y=-1代入3)

Let x be (1/a),y be (1/b):(設x為(1/a))(設y為1/b)

(2)好像(1),因为1/a变成x,1/b变成y,1/a=x=2,1/a=2,a=0.5,1/b=y=1/b=1,b=1,so a=0.5,b=1