a purse at radius 2.00m and a wallet at radius 3.00m travel in uniform circular motion on the floor of a merry-go-around as the ride turns. they are on the same radial line. at one instant, the acceleration of the purse is (2.00 m) i + (4.00 m) j. at that instant and in unit-vector notation, what is the acceleration of the wallet?
the answer is (3.00 m) i + (6.00 m) j.
Please explain why that is the answer ?? explain in details !!!!
thank you very much!!!
physics-circular motion
2010-09-29 2:02 pm
回答 (1)
2010-09-29 7:13 pm
✔ 最佳答案
Acceleration a = r.w^2where r is the radius of the circular motion and w is the angular velocity Since the angular velocities of the purse and wallet are the same, hencea = 2.w^2and a’ = 3.w^2where a and a’ are the accelerations of the purse and wallet respectively thus a’/a = 3/2i.e. a’ = (3/2).a = (3/2).[(2m).i + (4m).j] m/s^2 = [(3m).i + (6m).j] m/s^2
收錄日期: 2021-04-29 17:37:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100929000051KK00224