連式加答題
(2a+1)(3a)
-y(2y2-y+1)
2x(3x+y)
(k+1)(k+2)
(2p-3)(2p+5)
(6+m)(m-4)
(2x+y)(3x-2y)
中二數學多項式(三)
2010-09-29 4:38 am
回答 (2)
2010-09-29 4:50 am
✔ 最佳答案
1. (2a+1)(3a)= (3a)(2a) + 3a
= 6a^2 + 3a
2. -y(2y^2 - y + 1)
= -2y^3 + y^2 - y
3. 2x(3x+y)
= 6x^2 + 2xy
4. (k+1)(k+2)
= k^2 + k + 2k + 2
= k^2 + 3k + 2
5. (2p-3)(2p+5)
= 4p^2 - 6p + 10p - 15
= 4p^2 + 4p - 15
6. (6+m)(m-4)
= 6m + m^2 - 4m - 24
= m^2 + 2m - 24
7. (2x+y)(3x-2y)
= 6x^2 + 3xy - 4xy - 2y^2
= 6x^2 - xy - 2y^2
參考: Knowledge is power.
2010-09-29 7:01 am
1. (2a+1)(3a)
= (3a)(2a) + 3a(1)
= 6a^2 + 3a
2. -y(2y^2 - y + 1)
= -2y^3 + y^2 - y
= y^2 - 2y^3 - y
3. 2x(3x+y)
= 6x^2 + 2xy
4. (k+1)(k+2)
= k^2 + 2k + k + 2
= k^2 + 3k + 2
5. (2p-3)(2p+5)
= 4p^2 + 10p - 6p - 15
= 4p^2 + 4p - 15
6. (6+m)(m-4)
= 6m - 24 + m^2 - 4m
= m^2 + 2m - 24
7. (2x+y)(3x-2y)
= 6x^2 - 4xy + 3xy - 2y^2
= 6x^2 - xy - 2y^2
= (3a)(2a) + 3a(1)
= 6a^2 + 3a
2. -y(2y^2 - y + 1)
= -2y^3 + y^2 - y
= y^2 - 2y^3 - y
3. 2x(3x+y)
= 6x^2 + 2xy
4. (k+1)(k+2)
= k^2 + 2k + k + 2
= k^2 + 3k + 2
5. (2p-3)(2p+5)
= 4p^2 + 10p - 6p - 15
= 4p^2 + 4p - 15
6. (6+m)(m-4)
= 6m - 24 + m^2 - 4m
= m^2 + 2m - 24
7. (2x+y)(3x-2y)
= 6x^2 - 4xy + 3xy - 2y^2
= 6x^2 - xy - 2y^2
參考: me
收錄日期: 2021-04-25 17:02:58
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