Quadratic equation

a)
Sum of roots=(3k+2)/10
Product of roots=k/10

If the sum of roots is greater than the product of its roots by 4 over 5,
(3k+2)/10-k/10=4/5
2k+2=10(4/5)
2k+2=8
2k=6
k=3

b)
10x^2-11x+3=0
(2x-1)(5x-3)=0
x=1/2 or x=3/5