f.4 quadratic formula (urgent)

2010-09-29 2:56 am
1. If one root of x^2 + 5x +2t = 0 is -9, find
(a)the other root,
(b)the value of t.


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回答 (1)

2010-09-29 3:28 am
✔ 最佳答案
1a)- 9 + the other root = - 5the other root = 4b)(- 9)(4) = 2tt = - 182a)ab/(a+b) = (-1/3) / (4/3) = - 1/4b)2/a + 2/b= (2b + 2a) / ab= 2(a+b) / (ab)= 2(4/3) / (- 1/3)= - 8c)(a^2)b + ab^2= ab(a + b)= (-1/3)(4/3)= - 4/93a)Sum of the roots : -a/2 + (-b/2) = - (a + b)/2 = - (12/4)/2 = - 3/2Product of the roots : (-a/2)(-b/2) = ab/4 = (1/4)/4 = 1/16The equation is x^2 - (-3/2)x + 1/16 = 0x^2 + (3/2)x + 1/16 = 016x^2 + 24x + 1 = 0b)Sum of the roots = (a - 1)+(b - 1) = a + b - 2 = 12/4 - 2 = 1Product of the roots = (a - 1)(b - 1) = ab - (a+b) + 1 = 1/4 - 12/4 + 1 = - 7/4The equation is x^2 - 1x + (-7/4) = 04x^2 - 4x - 7 = 0


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