application of integration

2010-09-27 8:40 pm
A stone is thrown vertically upwards from an initial height of 40 m above
sea level with a velocity 10m/s. The downward accerlation due to the gravity is 10m/s^2 .
a)find the height of the stone at time t s.
b)when does the stone reach 25m above sea level?
c)what is the maximum height that the stone attains?

ans:
a) (-10e^-t)+10 m/s
b)3 s
c)45m

pls show clear steps,thx!
更新1:

why the velocity v at time t=10-10t? how can you get this?

回答 (1)

2010-09-27 9:54 pm
✔ 最佳答案
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2010-09-27 13:55:05 補充:
http://img824.imageshack.us/img824/9144/59420330.png


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