高數(高中)...微分法...pls help ><"

2010-09-27 3:49 am
( with working...thank you very much)

1) 已知 y=x^2.e^-x2

當x=1, 求dy/dx

2) y=√x + 1/√x
求dy/dx

3) y= √ (1-x / +x)

求dy/dx

(thank you soo much ><")

回答 (1)

2010-09-27 4:11 am
✔ 最佳答案
As follows:


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