急問2條數學(M1書數)

👨🏻‍🏫 學術台數學

[匿名]

2010-09-27 2:04 am

Given that A and B are independent events with P(A) = 0.82, P(B) = 0.62 , find:

a) P(A and B / A or B)
b) P(A / A or B)

佢個ANS係
0.5457
0.8802

但係求極個答案都錯, 請有心人列式教下我
THANKS

更新1:

a) P(A∩B │ A ∪B) b) P(A │ A ∪B)

更新2:

佢係一條來的, 即a要求: the probability of A∩B given A∪B

回答 (3)

螞蟻雄兵

2010-09-27 2:39 am

✔ 最佳答案

Given that A and B are independent eventswith P(A) = 0.82, P(B) = 0.62 , find:
a) P(A and B｜ A or B)
SolP(A or B)=P(A)+P(B)－P(AB)=0.82+0.62－0.82*0.62=0.9316P(A and B ｜A or B)
=P(P(A and B)/P(A or B)
=0.82*0.62/0.9316=0.5757277b) P(A｜A or B)
SolP(A｜A or B)
=P(A)/P(A or B)=0.82/0.9316=0.880206

👍 0 👎 0

[匿名]

2010-09-27 2:33 am

a) P(A∩B │ A ∪B)
b) P(A │ A ∪B)

2010-09-26 18:46:41 補充：
Thanks, 已解決, 原來禁簡單, 想得太複雜了~_~

2010-09-26 18:47:33 補充：
同埋螞蟻雄兵你第一條式對, 但計錯左個答案, anyway, thx ^^

👍 0 👎 0

STEVIE-G™

2010-09-27 2:29 am

Is it P(A and B) /P( A or B) ?

2010-09-26 18:37:09 補充：
okay~~

👍 0 👎 0

收錄日期: 2021-04-22 00:51:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100926000051KK01392

檢視 Wayback Machine 備份