plane perpendicular anotherone

👨🏻‍🏫 學術台數學

[匿名]

2010-09-26 11:43 pm

find an equation of the plane through the points P1(-2,1,4) and P2(1,0,4) that is perpendicular to the plane 4x-y+3z=2.

更新1:

how to get the equation (1)? can you explain?

更新2:

ok i know it is dot product thanks

回答 (1)

用戶9112

2010-09-27 12:02 am

✔ 最佳答案

Let the plane be ax+by+cz=1Since it is perpendicular to 4x-y+3z=2=>4a-b+3c=0…(1)Since the plane contains P1 and P2 so-2a+b+4c=1…(2)a+4c=1…(3)(3)=>a=1-4c(1)+(2)=>2a+7c=12(1-4c)+7c=12-8c+7c=1c=1=>a=-3Sub into (1), -12-b+3=0=>b=-9Therefore equation of the plane is-3x-9y+z=1

👍 0 👎 0

收錄日期: 2021-04-23 23:23:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100926000051KK01054

檢視 Wayback Machine 備份