Mathematics

2010-09-24 5:44 am
y=x二次-6x+9 which touches the x-axis at one point P , and cuts the y-axis at the point Q. Fing OP:OQ

回答 (1)

2010-09-24 5:51 am
✔ 最佳答案
y=x^2-6x+9=(x-3)^2

When y=0, x=3 => P=(3,0)
When x=0, y=9 => Q=(0,9)

So, OP=3 and OQ=9 => OP:OQ=3:9=1:3


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