正負數!!救我ar!!!
1)(-5x)+7x=?
2)(-2a)+(-15a)=?
3)(-8份之5a)+(-4份之0a)=?
請列式!!!
回答 (5)
✔ 最佳答案
1)(-5x)+7x
=-5x+7x
=2x
2)(-2a)+(-15a)
=-2a-15a
=-17a
3)(-8份之5a)+(-4份之0a)
=(5a/-8)-0a/4
=-5a/8-0
=-5a/8(又可寫成-0.625a)
參考: 自己
1)
(-5x) + 7x
= 7x - 5x
= 2x
______________________
2)
(-2a) + (-15a)
= -2a - 15a
= -17a
______________________
3)
你是說 5a/(-8) + a/(-4),而不是 5a/(-8) + (0a)/(-4) 嗎?如果是的話,那麼:
5a/(-8) + a/(-4)
= -5a/8 + (2/2)(-a/4)
= -5a/8 - 2a/8
= -7a/8
1.(-5x)+7X
=-5x+7x
=2x
2.(-2a)+(-15a)
=-2a-15a
=-17a
3.(5a/-8)+(a/4) <----你條式寫得唔好,a前面唔會係0,係1
=5a/-8+2a/-8
=5a+2a/-8
=7a/-8
參考: me
1. (-5x)+7x
= -5x+7x
= (-5+7)(x)
= 2x
2. (-2a)+(-15a)
= -2a -15a
= (-2 -15)(a)
= -17a
3. (-8份之5a)+(-4份之0a)
= -5a/8 +( -0/4)
= -5a/8 +0
= -5a/8
參考: myself =]
1.(-5x)+7x
=-5x+7x
=2x
2.)(-2a)+(-15a)
=-2a-15a
=-17a
3.(-8份之5a)+(-4份之0a)
=-8份之5a-4份之0a
**咩叫0a
收錄日期: 2021-05-01 13:21:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100923000051KK01186
檢視 Wayback Machine 備份