指數方程:
2^x+2^x-2=32
答案:2.91
對數方程:
log(x+2)+log4=1
答案:1/2
我想要過程...唔該!!!!
更新1:
指數既打錯......... 應該係.... 2^(x+2) +2^(x-2)=32
數學,指數同對數方程!!!!急!!
2010-09-23 11:57 pm
解.....
指數方程:
2^x+2^x-2=32
答案:2.91
對數方程:
log(x+2)+log4=1
答案:1/2
我想要過程...唔該!!!!
指數方程:
2^x+2^x-2=32
答案:2.91
對數方程:
log(x+2)+log4=1
答案:1/2
我想要過程...唔該!!!!
回答 (1)
2010-09-24 12:13 am
✔ 最佳答案
2^(x+2) +2^(x-2)=32 (2^2)(2^x) + (2^-2)(2^x) = 32(2^x) (4 + 1/4) = 322^x = 7.52941x log 2 = log 7.52941x = 2.91log(x+2)+log4=1log [ (x+2)(4) ] = 1log [ 4(x+2) ] = log 104(x+2) = 10x = 10/4 - 2x = 1/2
收錄日期: 2021-04-21 22:17:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100923000051KK00356