1.
3^2 2^-2
-------------
3^-3 2
2.
(2^3)^n
------------
2^3n+1
兩條整數指數定律...急
2010-09-23 11:24 pm
回答 (2)
2010-09-24 12:17 am
✔ 最佳答案
3^2 2^-2-------------
3^-3 2
______________
3^2-(-3)*2^-2-1
3^5*2^-3
243/8
____________________
(2^3)^n
------------
2^3n+1
______________
2^3n/2^3n+1
1/2^3n+1-3n
1/2
2010-09-23 11:36 pm
1. 3^2 . 2^-2/3^-3 . 2
= 3^2+3 . 2^-2-1
= 3^5 . 2^-3
= 3^5 / 2^3
2. (2^3)^n / 2^3n+1
= 2^3n / 2^3n+1
= 2^3n-3n-1
= 2^-1
= 1/2
= 3^2+3 . 2^-2-1
= 3^5 . 2^-3
= 3^5 / 2^3
2. (2^3)^n / 2^3n+1
= 2^3n / 2^3n+1
= 2^3n-3n-1
= 2^-1
= 1/2
收錄日期: 2021-05-03 11:54:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100923000051KK00244