When 10cm^3 of a gaseous hydrocarbon, C3Hx, was burnt with an excess of oxygen at 110'C. The volume measured under the same conditions expanded by 5cm^3. What is the value of x, and what volume of oxygen was used under these conditions?
Please give me detail explanation... Thanks!
AL Chemistry mole calculation
2010-09-23 7:07 am
回答 (1)
2010-09-23 7:51 am
✔ 最佳答案
C3Hx + [3 + (x/4)]O2 → 3CO2 + (x/2)H2OVolume of C3Hx used = 10 cm³
Volume of O2 used = 10*[3 + (x/4)] = (30 + 2.5x) cm³
Volume of CO2 formed = 3*10 = 30 cm³
Volume of H2O formed = (x/2)*10 = 5x cm³
Expansion in volume:
30 + 5x - 10 - (30 + 2.5x) = 5
2.5x -10 = 5
2.5x = 15
x = 6
Volume of O2 used = 30 + 2.5(6) = 45 cm³
參考: adam
收錄日期: 2021-04-16 11:41:42
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