F.4 AMATHS(differentiation)
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F.4 AMATHS(differentiation)
2010-09-19 9:30 pm
回答 (2)
2010-09-19 9:45 pm
2010-09-19 10:20 pm
y = ln√(6 - 2x) = [ln(6 - 2x)]/2
y' = [1/(6 - 2x)](-2)/2 = 1/(2x - 6)
y' = [1/(6 - 2x)](-2)/2 = 1/(2x - 6)
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100919000051KK00801