sqrt(2sqrt(2sqrt(2sqrt(2......
=2
我想知solution 同點解?
thx...
F.4 MATNs
2010-09-18 7:06 am
回答 (2)
2010-09-18 8:03 am
2010-09-18 8:57 am
Let y=sqrt(2sqrt(2sqrt(2sqrt(2......
=> y^2=2sqrt(2sqrt(2sqrt(2......
(y^2)/2=sqrt(2sqrt(2sqrt(2......
(y^2)/2=y
y(y/2-1)=0
=> y=0 (rej.) or y/2=1 => y=2=sqrt(2sqrt(2sqrt(2sqrt(2......
=> y^2=2sqrt(2sqrt(2sqrt(2......
(y^2)/2=sqrt(2sqrt(2sqrt(2......
(y^2)/2=y
y(y/2-1)=0
=> y=0 (rej.) or y/2=1 => y=2=sqrt(2sqrt(2sqrt(2sqrt(2......
收錄日期: 2021-04-25 16:59:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100917000051KK01512