suppose z varies directly as x and inversely as y^2.
when x=y=4,z=2. when x=y=8, z= ????
點解個ANS係1?
f.5 maths partial variation
2010-09-18 2:39 am
回答 (1)
2010-09-18 3:09 am
✔ 最佳答案
z varies directly as x and inversely as y^2=> z=kx/y^2, where k is a real number
when x=y=4,z=2:
2=k(4)/(4)^2
k=8
So, z=8x/y^2
When x=y=8, z=8(8)/8^2=1
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100917000051KK00859