proof:
sin (nθ) /sinθ = 2^(n-1) (cosθ -cos(π/n))(cosθ -cos(2π/n))...(cosθ -cos((n-1)π/n))
收錄日期: 2021-04-22 00:51:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100917000051KK00729