數學log 問題x1
2010-09-16 6:50 am
回答 (2)
2010-09-16 5:12 pm
✔ 最佳答案
10 log [ ( 0.6 x π x r^2) / 1 x 10^-12 ] = 82log [ ( 0.6 x π x r^2) / 1 x 10^-12 ] = 82/10
log [ ( 0.6 x π x r^2) / 1 x 10^-12 ] = 8.2
( 0.6 x π x r^2) / (1 x 10^-12) = 10^8.2
( 0.6 x π x r^2) = 10^8.2(1 x 10^-12)
( 0.6 x π x r^2) = 10^(-3,8)
r^2 = 10^(-3,8)/(0.6 x π)
r^2 = 10^(-3,8)/(0.6 x π)
r^2 = 1/(10^3.8 x 0.6 x π)
r^2 = 1/111893.26575
r^2 = 0.00008404
r = square root of (0.00008404)
r = 0.009169 or r = 9.169 x 10^(-3)
2010-09-16 7:16 am
log [ ( 0.6 x π x r^2) / 1 x 10^-12 ] = 82/10
( 0.6 x π x r^2) / 1 x 10^-12 = 10^8.2
r = 8.41 x 10^-5
( 0.6 x π x r^2) / 1 x 10^-12 = 10^8.2
r = 8.41 x 10^-5
收錄日期: 2021-04-13 17:31:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100915000051KK01561