(1) 4p-5q-16p^2+40pq-25q^2
(2) h^4-1
Answer:
(1) (4p-5q)(1-4p+5q)
(2) (h^2+1)(h+1)(h-1)
[F.3]急Factorization(20分有答案求步驟)
2010-09-16 2:03 am
回答 (1)
2010-09-16 2:09 am
✔ 最佳答案
(1) 4p-5q-16p^2+40pq-25q^2= (4p - 5q) - (16p^2 - 40pq + 25q^2)= (4p - 5q) - [(4p)^2 - 2(4p)(5q) + (5q)^2]= (4p - 5q) - (4p - 5q)^2= (4p - 5q)[1 - (4p - 5q)]= (4p - 5q)(1 - 4p + 5q)2)h^4 - 1= (h^2)^2 - 1^2= (h^2 + 1)(h^2 - 1)= (h^2 + 1)(h + 1)(h - 1)
收錄日期: 2021-04-21 22:15:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100915000051KK00840