A Canadian, driving in the U.S.A., fuels their car at a cost of US$3.84 per gallon (US).
The current monetary exchange rate is 0.934 US$/Can$.
The density of the fuel is 0.655 g/mL.
What is the mass of Can$40.00-worth of this fuel?
1 U.S. gallon = 3.7854 liters.
If the vehicle consumes the gasoline at a rate of 5.60 L/100 km, how many miles can it travel on the above amount of gasoline?
miles
chemistry help 15 pts
2010-09-15 4:31 pm
回答 (2)
2010-09-15 6:05 pm
✔ 最佳答案
Converting from Can$ to US$:Can$ 40.00 = US$ 40.00 x 0.934 = US$ 37.36
Hence, amount of fuel, in gallon that can be bought is:
37.36/3.84 = 9.729 U.S. gallon
Converting to litre, it is equal to 9.729 x 3.7854 = 36.829 L
Hence mass = 0.655 x 36.829 x 1000 = 24123 g = 24.123 kg
With this amount of fuel, distance that can be travelled is:
36.829/5.6 x 100 = 657.7 km
參考: Myself
2010-09-15 6:03 pm
Mass of gasoline= (0.934 x 40)/3.84 x 3.7854 /0.655 x1000 = 56227,1565 gm =56.2272 Kg
length of travelling = 0.934 x 40/3.84 x 3.7845 / 5.6 x100 = 657.6569 Km
length of travelling = 0.934 x 40/3.84 x 3.7845 / 5.6 x100 = 657.6569 Km
收錄日期: 2021-04-13 17:30:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100915000051KK00195