f.4 quadratic formula 2 (1q)
回答 (2)
2010-09-14 3:27 am
✔ 最佳答案
1)x^2 - 2x + 4/3 = 0
Mutiply the equation by 3,
3x^2 - 6x + 4 = 0
delta
= 36 - 4(3)(4)
= 36 - 48
= -12 < 0
So, no real solutions.
2010-09-13 19:42:37 補充：
唔係呀!!!
根本呢一條式都無實數答案，
DELTA小於0，NO REAL SOLUTION....
你係唔係要complex number???
f.4 應該未學到
2010-09-14 3:48 am
x^2 - 2x +4/3 = 0
3x^2 - 6x +4 = 0
x= [6±√36-4(3)(4)]/2(3)
x= 1± √3/3 i
:)
p.s. i = √-1
3x^2 - 6x +4 = 0
x= [6±√36-4(3)(4)]/2(3)
x= 1± √3/3 i
:)
p.s. i = √-1
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