F4 Physics time

2010-09-12 11:00 pm
Problem:
1)The maximum error of the atomic caesium clock installed at hong Kong Observatory is 10^-6 per day.
2)John's watch runs slower than the actual time by one minute each day. John adjusted the watch to the correct time at 2:00 om on 1 January 2009.
(a) What time should be shown on Kohn's watch when the actual time is 2:00 pm on 10 January 2009? Explain your answer briefly.
(b) What is the percentage error of time shown on John's watch as compared with the correct time?
更新1:

The question of the first one is: (a) What is the possible percentage error? (b)How long would it take to be in error by 1s? Thank you so much!!

回答 (1)

2010-09-13 11:14 pm
✔ 最佳答案
1. There is no unit given in your question to the max error of 10^-6. I presume that it is 10^-6 second per day.
What is your question...?

2. What is 2:00om? Is it a typo of 2:00pm
(a) There are 9 complete days from 2:00pm on 1 January to 10 January, 2009. Total time lag on John's watch = 9 x 1 minutes = 9 minutes.
Hence, time shown on his watch = 1:51pm

(b) Percentage error = [9/(9 x 24 x 60)] x 100% = 0.069%


收錄日期: 2021-04-29 17:36:10
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