我想問一問負數既問題啊...
好似以下呢一題數感...
-12+[10-(-8又4分之3)-25]-(2-6又4分之1)
想問問係唔係要先計中括號先啊??
定係計括號先啊??
希望大家多多幫忙...
解釋一下點樣><
仲有仲有...
唔該大家比埋步驟我啊..
唔該哂^^
負數問題啊..Help~~20分ga...
2010-09-11 5:28 am
回答 (2)
2010-09-11 6:47 pm
✔ 最佳答案
先拆括號內的數，再拆中括號的數-12+[10-(-8又4分之3)-25]-(2-6又4分之1)
=-12+[ 10- (-35/4)-25]- (2- 25/4)
=-12+[ 10+35/4-25]-2+25/4
=-12+(-25/4)-2+25/4
=-12-25/4-2+25/4
=-12-2
=-14
參考: ME
2010-09-11 6:06 am
-12+[10-(8又3/4)-25]-(2-6又1/4)
=-12+[10-(35/4)-25]-(2-25/4)
=12+[-23.75]-(-4.25)
=12-23.75+4.25
=-7.5
=-12+[10-(35/4)-25]-(2-25/4)
=12+[-23.75]-(-4.25)
=12-23.75+4.25
=-7.5
收錄日期: 2021-04-19 23:13:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100910000051KK01313