Simplify it
2010-09-04 9:14 pm
If n is a positive integer,simplify it:
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回答 (3)
2010-09-04 9:29 pm
✔ 最佳答案
[a^(n+4) - a^3n] / [a^(3n+3) - a^(n+7)]= [a^(n+4)] [1 - a^(2n-4)] / {[a^(n+7)] [a^(2n-4) - 1]}= - [a^(n+4)] / a^(n+7)= - a^-3= - 1/a^3
2010-09-05 12:45 am
2010-09-04 10:05 pm
[a^(n+4) - a^(3n)] / [a^(3n+3) - a^(n+7)]
=[a^4 - a^(2n)] / [a^(2n+3) - a^7]
=[a^4 - a^(2n)] / { [a^(2n) - a^4][a^3] }
= - 1/a^3 or -a^(-3)
=[a^4 - a^(2n)] / [a^(2n+3) - a^7]
=[a^4 - a^(2n)] / { [a^(2n) - a^4][a^3] }
= - 1/a^3 or -a^(-3)
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100904000051KK00544