急~~中一正負數題!!20點~~

1.(-2)+(-3)=-2-3=-5

2.(+3)-(+6)=3-6=-3

3.(-1)-(+4)+(+2)=-1-4+2=-3

4.(-3)+(+7)-(+4)=-3+7-4=0

5.(+9)+(-4)=9-4=5

6.(-3)+(-6)=-3-6=-9

7.(+2)-(-3)=2+3=5

8.(+50)/(-25)=-(50/25)=-2

9.(-36)/(-9)=36/9=4

10.(-12)+(-1)+(-3)/(+2)=(-12-1-3)/2=-8 or -12-1-(3/2)=-29/2(-14/1/2 or-14.5)(我唔知你個除號你for where)

11.(-15)*(+2)(-2)/(+3)=(-15*2*-2)/3=20

12.(-2)*(-30)=2*30=60

1) (-2)+(-3)
= -2-3
= -5

2) (+3)-(+6)
=3-6
= -3

3) (-1)-(+4)+(+2)
= -1-4+2
= -3

4) (-3)+(+7)-(+4)
= -3+7-4
= 0

5. (+9)+(-4)
= 9-4
= 5

6. (-3)+(-6)
= -3-6
= -9

7. (+2)-(-3)
= 2+3
= 5

8. (+50)/(-25)
= 50/(-25)
= -2

9. (-36)/(-9)
= -36/(-9)
= +4

10. (-12)+(-1)+(-3)/(+2)
= -12-1+(-3)/2
= -14.5

11. (-15)*(+2)(-2)/(+3)
= -15*2*(-2)/3
= 20

12. (-2)*(-30)
= -2*(-30)
60

N=4(y-5),wherey =2
N= 4(2-5)
N= 4(-3)
N= -12

第8,9,10,11,12暝#,後邊個數係負數,所以要加括號

這裏可以幫到你
http://yahodnia.w13.dns-sky.com/yahoo.com.hk/hk/auction/178987536

N=4(y-5),wherey =2
N=4(2-5)
N=4(-3)
N=-12

1) (-2)+(-3)
= -2-3
=-5

2)(+3)-(+6)
=3-6
=-3

3.(-1)-(+4)+(+2)
=(-1)-4+2
=-3

4.(-3)+(+7)-(+4)
=(-3)+7-4
=0

5.(+9)+(-4)
=9-4
=5

6.(-3)+(-6)
=(-3)-6
=-9

7.(+2)-(-3)
=2+3
=5

8.(+50)/(-25)
=50/(-25)
=-2

9.(-36)/(-9)
=36/9
=4

10.(-12)+(-1)+(-3)/(+2)
=(-12)-1-3/2
=-8

11.(-15)*(+2)(-2)/(+3)
=(-15)*2*(-2)/3
=60/3
=20

12.(-2)*(-30)
=2*30
=60

2010-09-01 22:02:31 補充：
N=4(y-5),wherey =2
=4(2-5)
=4*(-3)
N=-12

1) -5
2) -3
3) -3
4) 0
5) 5
6) -9
7) 5
8) -2
9) 4
10) 我想問下..(-12)+(-1)+(-3) 有無[ ]?有就= -9
無就=-13 -3/+2
11) 我想問下..(-15)*(+2)(-2)有無[ ]?有就= 20
無就= -30 -2/+3
12) 60
希望幫到您(: