F4 Math - Polynomiais etc

2010-08-29 7:38 pm
http://img801.imageshack.us/img801/7505/math.png

Five questions are written on the pic. Please help me to solve them by clear steps n show the steps. Thanks : )

回答 (1)

2010-08-29 10:45 pm
✔ 最佳答案
1.1/(x^2-1)+1/(x-1)=0
Sol
1/(x^2-1)+1/(x-1)=0
1+(x+1)=0
x=-2

2. x-y=0,x^2-xy+y^2=5
Sol
x=y
x^2-x^2+x^2=5
x^2=5
x=+/-√5(1)x=√5,y=√5
(2)x=-√5,y=-√5

3. x+y=1,x^2-xy=15
Sol
y=1-x
x^2-x(1-x)=15
x^2-x+x^2=15
2x^2-x-15=0
(2x+5)(x-3)=0
x=-5/2 or x=3
(1) x=-5/2,y=7/2
(2) x=3,y=-2


4.[(6x^2-7x-20)/(x^2-4)]*[(x^2-x-2)/(6x-15)]/[(3x^2+7x+4)/(x^2+2x)]
Sol
[(6x^2-7x-20)/(x^2-4)]*[(x^2-x-2)/(6x-15)]/[(3x^2+7x+4)/(x+2+2x)]
=[(6x^2-7x-20)/(x^2-4)]*[(x^2-x-2)/(6x-15)]*[(x^2+2x)/(3x^2+7x+4)]
=[(6x^2-7x-20)*(x^2-x-2)*(x^2+2x)]/[(x^2-4)*(6x-15)*(3x^2+7x+4)]
=[(2x-5)(3x+4)*(x-2)(x+1)*x(x+2)]/[(x-2)(x+2)*3*(2x-5)*(x+1)(3x+4)]
=x/3

5. a/[(a-b)(a-c)+b/[(b-c)(b-a)]+c/](c-a)(c-b)]
Sol
A=a/[(a-b)(a-c)+b/[(b-c)(b-a)]+c/](c-a)(c-b)]
A(a-b)(b-c)(c-a)
=a(c-b)+b(a-c)+c(b-a)
=ac-ab+ab-bc+bc-ac
=0




收錄日期: 2021-04-15 18:14:05
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