Probability
2010-08-28 4:50 am
A bag contains red, blue and yellow balls. P(red) = 0.2, P(blue) = 0.5 and P(yellow) = 0.3. Some of the balls are marked with a letter 'X', P(Red ball marked with X) = 0.35, P(Blue ball marked with 'X') = 0.55, P(Yellow balls marked with 'X') = 0.35. Now 2 balls are drawn from the bag with replacement, find the probability that both balls are of same color and both are marked.
回答 (1)
2010-08-28 5:03 am
✔ 最佳答案
P(both balls are of same color and both are marked. )= P(both balls are red and both are marked) + P(both balls are blue and both are marked)+ P(both balls are yellow and both are marked)= (0.2)(0.35)(0.2)(0.35)+ (0.5)(0.55)(0.5)(0.55)+ (0.3)(0.35)(0.3)(0.35)
= 0.09155
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